TPTP Problem File: SYN990^1.p
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% File : SYN990^1 : TPTP v8.2.0. Released v3.7.0.
% Domain : Syntactic
% Problem : Simple test for satisfiability
% Version : Especial.
% English : There are two individuals, a and b. Everything is either a or b.
% There are three functions from individuals to individuals: f,g,h.
% They are all different.
% Refs : [Bro09] Brown (2009), Email to Geoff Sutcliffe
% Source : [Bro09]
% Names :
% Status : Satisfiable
% Rating : 0.00 v8.1.0, 0.33 v6.1.0, 0.00 v5.4.0, 0.67 v5.2.0, 1.00 v5.0.0, 0.33 v4.1.0, 0.00 v3.7.0
% Syntax : Number of formulae : 9 ( 3 unt; 5 typ; 0 def)
% Number of atoms : 5 ( 5 equ; 0 cnn)
% Maximal formula atoms : 2 ( 1 avg)
% Number of connectives : 4 ( 3 ~; 1 |; 0 &; 0 @)
% ( 0 <=>; 0 =>; 0 <=; 0 <~>)
% Maximal formula depth : 3 ( 2 avg)
% Number of types : 1 ( 0 usr)
% Number of type conns : 3 ( 3 >; 0 *; 0 +; 0 <<)
% Number of symbols : 6 ( 5 usr; 2 con; 0-2 aty)
% Number of variables : 1 ( 0 ^; 1 !; 0 ?; 1 :)
% SPC : TH0_SAT_EQU_NAR
% Comments :
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thf(a,type,
a: $i ).
thf(b,type,
b: $i ).
thf(f,type,
f: $i > $i ).
thf(g,type,
g: $i > $i ).
thf(h,type,
h: $i > $i ).
thf(ab,axiom,
! [X: $i] :
( ( X = a )
| ( X = b ) ) ).
thf(fg,axiom,
f != g ).
thf(gh,axiom,
g != h ).
thf(fh,axiom,
f != h ).
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